slacky.eu

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     *
    **
   ***
  ****
 *****
******

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#include <stdio.h>

void main(){
  for(int stars=1; stars <= 6; stars++)
    printf("%6.*s\n", stars, "******");
}

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#include <stdio.h>

#ifndef LENGTH
#define LENGTH 6
#endif


int main() {
        int i, j;

        for (i = 0; i < LENGTH; i++) {
                for (j = LENGTH - 1; j >= 0; j--) {
                        if (j <= i)
                                printf("*");
                        else
                                printf(" ");
                }
                printf("\n");
        }

        return 0;
}

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#ifndef LENGTH
#define LENGTH 6
#endif

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 int i, j;

        for (i = 0; i < LENGTH; i++) {
                for (j = LENGTH - 1; j >= 0; j--) {
                        if (j <= i)
                                printf("  ");
                        else
                                printf("*");
                }
                printf("\n");
        }

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%6.*s

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#include<stdio.h>
main()
{
 int i,k,j,lato;
 printf("\nInserisci valore lato:");
 scanf("%d",&lato);
 for(i=1;i<=lato;i++){
                               for(j=lato-i;j>0;j--)
                                                             printf("    ");
                               for(k=i;k>0;k--)
                                                              printf("*");
                                printf("\n");
                                }
 return 0;
 }

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%6.*s

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...The character % is followed by zero or more of the following flags:...
...An  optional decimal digit string (with nonzero first digit) specifying a minimum field width. If the converted value has fewer characters than the field width, it will be padded with spaces on the left...
...An optional precision, in the form of a period ('.')  followed by an optional decimal digit string. Instead of a decimal digit string one may write "*" to specify that the precision is given in the next argument...the maximum number of characters to be printed from a string for s and S conversions...
...s      If no l modifier is present: The const char * argument is expected to be a pointer to an array of character type (pointer to a string)...

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#include <stdio.h>
#include <stdlib.h>
#include <string.h>

#define DEFAULT_LENGTH 1


int main() {
	int i, l;

	printf("Inserisci la lunghezza massima della riga: ");
	scanf("%d", &l);

	if (l <= 0)
		l = DEFAULT_LENGTH;

	printf("Metodo targzeta\n");
	char *stars = calloc(l + 1, sizeof(char));
	memset(stars, '*', l);
	for (i = 0; i < l; i++)
		printf("%*.*s\n", l, i + 1, stars);
	free(stars);

	printf("\n\nMetodo Ansa89\n");
	int j;
	for (i = 0; i < l; i++) {
		for (j = l - 1; j >= 0; j--) {
			if (j <= i)
				printf("*");
			else
				printf(" ");
		}
		printf("\n");
	}

	printf("\n\nMetodo SlackNewbie\n");
	for (i = 1; i <= l; i++) {
		for (j = l - i; j > 0; j--)
			printf(" ");
		for (j = i; j > 0; j--)
			printf("*");
		printf("\n");
	}

	return 0;
}

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#include <stdio.h>

int blank,stars;

void main(){

 for(blank=1; blank < 7; blank++) {
  printf("%*c", 7-blank, 0);
  for (stars=7; stars > 7-blank; stars--) printf("*");
  printf ("\n");
 }
}